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CsdLean4.LF3.Singlet.Expectations

LF3 Singlet / Expectations: the headline 4×4 Pauli expectation calculation #

Category: 3-Local (LF3 left/right zero expectations and singlet_pauli_correlation = −a·b).

Paper §6.

Three theorems on the Bell singlet:

Strategy: a single helper lemma expectation_formula reduces the expectation on any (Fin 2 × Fin 2)-indexed matrix to a (1/2) · (sum of 4 entries) form. The three theorems then evaluate the entries of sigmaDotLeft / Right / Joint.

The proof of expectation_formula is a 4×4 inner-product unfolding: reduce to a dot product via EuclideanSpace.inner_eq_star_dotProduct, expand both sums over Fin 2 × Fin 2, push star past pointwise application with Pi.star_apply, substitute the four singlet_apply_* values (12 of 16 terms vanish from factors of zero), and close with ring_nf + the ((√2)⁻¹)² = 1/2 helper.

Auxiliary: at index (0, 0) the singlet is zero.

Auxiliary: at index (0, 1) the singlet is 1/√2.

Auxiliary: at index (1, 0) the singlet is −1/√2.

Auxiliary: at index (1, 1) the singlet is zero.

theorem CSD.LF3.inv_sqrt_two_sq :
(↑2)⁻¹ * (↑2)⁻¹ = 1 / 2

Squaring the real (√2)⁻¹ coerced to gives 1/2.

theorem CSD.LF3.expectation_formula (M : Matrix (Fin 2 × Fin 2) (Fin 2 × Fin 2) ) :
expectation M = 1 / 2 * (M (0, 1) (0, 1) - M (0, 1) (1, 0) - M (1, 0) (0, 1) + M (1, 0) (1, 0))

Expectation formula. On the Bell singlet, the expectation of an arbitrary (Fin 2 × Fin 2)-indexed matrix reduces to a half-sum over four specific matrix entries. The 12 of 16 double-sum terms vanish (each has a singlet (0,0) = 0 or singlet (1,1) = 0 factor); the surviving 4 factor through ((√2)⁻¹)² = 1/2.

Pauli matrix entries (auxiliaries) #

pauliDot a 0 0 = a_z (as a complex number).

pauliDot a 0 1 = a_x − i a_y.

pauliDot a 1 0 = a_x + i a_y.

pauliDot a 1 1 = −a_z.

The three headline expectations (paper §6.7, §6.8) #

Singlet left-Pauli expectation vanishes. ⟨ψ⁻ | σ·a ⊗ I | ψ⁻⟩ = 0.

Singlet right-Pauli expectation vanishes. ⟨ψ⁻ | I ⊗ σ·b | ψ⁻⟩ = 0.

Singlet two-Pauli correlation. ⟨ψ⁻ | σ·a ⊗ σ·b | ψ⁻⟩ = -a·b.